Determine the velocity of the 0.97-kg fragment immediately after the explosion.

A 2.97-kg projectile is fired with an initial speed of 122 m/s at an angle of 31° with the horizontal. At the top of its trajectory, the projectile explodes into two fragments of masses 0.97 kg and 2 kg. At 3.51 s after the explosion, the 2-kg fragment lands on the ground directly below the point of explosion.

(a) Determine the velocity of the 0.97-kg fragment immediately after the explosion.

vector v1 =313.723 m/s i + 80.382 m/s j

(b) Find the distance between the point of firing and the point at which the 0.97-kg fragment strikes the ground.

_______________________________km

(c) Determine the energy released in the explosion

__________________________ kJ

I know part A is right, I just need help with part B & C