Using the information below, calculate H of NH3(g)+HCl(g)NH4Cl(s). 12N2(g)+32H2(g)NH3(g)H=46.19kJ/mol 12H2(g)+12Cl2(g)HCl(g)H=92.30kJ/mol…

1.Using the information below, calculate ΔH of NH3(g)+HCl(g)⟶NH4Cl(s).

12N2(g)+32H2(g)⟶NH3(g)ΔH=−46.19kJ/mol

12H2(g)+12Cl2(g)⟶HCl(g)ΔH=−92.30kJ/mol

12N2(g)+2H2(g)+12Cl2(g)⟶NH4Cl(g)ΔH=−314.4kJ/mol

Your answer should have four significant figures.

2.Calculate the ΔH∘reaction for

4NH3(g)+5O2(g)⟶4NO(g)+6H2O(g)

given ΔH∘f(NH3)=−46.19kJ/molΔH∘f(NO)=90.37kJ/molΔH∘f(H2O)=−241.82kJ/mol.

3.Using the information below, calculate ΔH of NO(g)+12O2(g)⟶NO2(g).

12N2(g)+O2(g)⟶NO2(g)ΔH=33.84kJ/mol

NO(g)⟶12O2(g)+12N2(g)ΔH=−90.37kJ/mol

4.Complete the chemical equation for the formation of hydrogen fluoride, HF(g). Remember fractional coefficients are possible when balancing equations for the purpose of determining heat of formation.