calculate the maximum number of moles and grams of H2S that can form when 208.5g of aluminum sulfide reacts with 175.2g of water: Al 2 S 3 +6H 2 O =

calculate the maximum number of moles and grams of H2S that can form when 208.5g of aluminum sulfide reacts with 175.2g of water:

Al2S3+6H2O = 2Al(OH)3+3H2S

___?___ mol H2S

___?___ g H2S

What mass of the excess reactant remains?

___?___ g excess reactant 

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