A constant torque of 25.0 N m is applied to a grindstone whose moment of inertia is 0.130 kg m2.

A constant torque of 25.0 N ∙ m is applied to a grindstone whose moment of inertia is 0.130 kg ∙ m2. Using energy principles and neglecting friction, find the angular speed after the grindstone has made 15.0 revolutions. (Hint: The angular equivalent of Wnet = FΔx = 1/2 mvf2 – 1/2 mvi2 is Wnet = τΔθ = 1/2 Iωf2 – 1/2 Iωi2. You should convince yourself that this relationship is correct.)